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The common geometry of a 3.5" floppy disk has 18 sectors per track
with two heads and 80 cylinders. Thus, optimising the dd
command to read the contents of a floppy we would use:
$ dd bs=2x80x18b if=/dev/fd0 of=/tmp/floppy.image
1+0 records in
1+0 records out
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Then to write to another floppy:
$ dd bs=2x80x18b < /tmp/floppy.image > /dev/fd0
1+0 records in
1+0 records out
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The 2x multiplies the sector size by the number of heads
while the 80x identifies the number of cylinders. The
18b specifies 18 sectors of 512 bytes. This gives a total of
1,474,560 bytes and issues a single 1,474,560-byte read request to
/dev/fd0 and a single 1,474,560 write request to /tmp/floppy.image,
rather than the corresponding cp command:
$ cp /dev/fd0 /tmp/floppy.image
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which issues 360 reads and writes of 4,096 bytes each.
Copyright © 1995-2006 [email protected]
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